The 5V Power Supply Unit (PSU), manufactured by Conor Curley, is a compact and reliable power source designed to provide a stable 5-volt output. This PSU is ideal for powering a wide range of electronic circuits and devices, ensuring consistent voltage for reliable operation. It is commonly used in microcontroller-based projects, sensors, and low-power electronic devices.
The following table outlines the key technical details of the 5V PSU:
Parameter | Specification |
---|---|
Manufacturer | Conor Curley |
Output Voltage | 5V DC ± 5% |
Input Voltage Range | 7V - 12V DC |
Maximum Output Current | 1A |
Efficiency | ≥ 85% |
Ripple Voltage | ≤ 50mV |
Operating Temperature | -20°C to +70°C |
Dimensions | 25mm x 20mm x 15mm |
Weight | 10g |
Pin Name | Description |
---|---|
VIN | Input voltage (7V - 12V DC) |
GND | Ground (common reference for input and output) |
VOUT | Regulated 5V DC output |
VIN
pin. Ensure the input voltage is within the specified range to avoid damage.GND
pin to the ground of your circuit.VOUT
pin to power your 5V devices or circuits.Below is an example of using the 5V PSU to power an Arduino UNO and a sensor:
+-------------------+ +-------------------+
| DC Power Supply | | Arduino UNO |
| (7V - 12V) | | |
| | | |
| +---- VIN ------+-------+ VIN |
| | | | |
| +---- GND ------+-------+ GND |
| | | |
+-------------------+ +-------------------+
The 5V PSU is commonly used to power Arduino projects. Below is an example code to read data from a temperature sensor (e.g., LM35) powered by the 5V PSU:
// Example: Reading temperature data from an LM35 sensor
// Ensure the LM35 is powered by the 5V PSU's VOUT pin
const int sensorPin = A0; // LM35 sensor connected to analog pin A0
void setup() {
Serial.begin(9600); // Initialize serial communication at 9600 baud
}
void loop() {
int sensorValue = analogRead(sensorPin); // Read the analog value from the sensor
float voltage = sensorValue * (5.0 / 1023.0); // Convert to voltage (5V reference)
float temperature = voltage * 100.0; // Convert voltage to temperature (°C)
Serial.print("Temperature: ");
Serial.print(temperature);
Serial.println(" °C");
delay(1000); // Wait 1 second before the next reading
}
VOUT
pin of the PSU to the 5V
pin of the Arduino UNO.GND
pin.Issue | Possible Cause | Solution |
---|---|---|
No output voltage | Incorrect input voltage or polarity | Verify input voltage and polarity |
Output voltage is unstable | Overloading the PSU | Reduce the load to within 1A limit |
PSU overheating | Operating near maximum current limit | Improve ventilation or reduce load |
Connected device not working | Loose or incorrect connections | Check all connections and wiring |
Q1: Can I use the 5V PSU to power a Raspberry Pi?
A1: No, the Raspberry Pi typically requires a higher current (2.5A or more). This PSU is limited to 1A and is not suitable for powering a Raspberry Pi.
Q2: What happens if I exceed the input voltage range?
A2: Exceeding the input voltage range (7V - 12V) may damage the PSU. Always use a regulated DC power source within the specified range.
Q3: Can I use this PSU to power multiple devices?
A3: Yes, as long as the total current draw does not exceed 1A. Ensure proper wiring and connections.
Q4: Is the PSU protected against short circuits?
A4: This PSU does not include built-in short-circuit protection. Avoid shorting the output pins to prevent damage.
The 5V Power Supply Unit (PSU) by Conor Curley is a versatile and reliable component for powering low-power electronic devices and circuits. Its stable 5V output and compact design make it an essential tool for hobbyists, students, and professionals working on microcontroller-based projects. By following the usage instructions and best practices outlined in this documentation, you can ensure safe and efficient operation of the PSU in your projects.